5y^2-29y^2-6y=0

Solution for 5y^2-29y^2-6y=0 equation:

5y^2-29y^2-6y=0

We add all the numbers together, and all the variables

-24y^2-6y=0

a = -24; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-24)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-24}=\frac{0}{-48}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-24}=\frac{12}{-48}
=-1/4
$